Y=3x^2+5x+17

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Solution for Y=3x^2+5x+17 equation: 



=3Y^2+5Y+17

We move all terms to the left:

-(3Y^2+5Y+17)=0

We get rid of parentheses

-3Y^2-5Y-17=0

a = -3; b = -5; c = -17;
Δ = b2-4ac
Δ = -52-4·(-3)·(-17)
Δ = -179
Delta is less than zero, so there is no solution for the equation

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